2c^2-14c-36=0

Solution for 2c^2-14c-36=0 equation:

2c^2-14c-36=0

a = 2; b = -14; c = -36;
Δ = b2-4ac
Δ = -142-4·2·(-36)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-22}{2*2}=\frac{-8}{4}
=-2
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+22}{2*2}=\frac{36}{4}
=9
$